problems

Hack 1, 3.6.3: Conditionals

# Example of Python Conditionals with comments

# Step 1: Set an example value for age
age = 18

# Step 2: Use an if statement to check if the age is less than 18
if age < 18:
    # This block runs if the condition is True
    print("You are a minor.")

# Step 3: Use an elif statement to check if age equals 18
elif age == 18:
    # This block runs if the age is exactly 18
    print("You just became an adult!")

# Step 4: Use an else statement for any other cases (age greater than 18)
else:
    # This block runs if none of the previous conditions were True
    print("You are an adult.")

You just became an adult!

Hack 2, 3.6.2: Js conditional

// Function to get a grade based on score
function getGrade() {
    // Prompt the user to input a score
    let score = prompt("Enter the score (0-100):");
    score = Number(score);  // Convert input to a number

    // Check if the input is a valid number
    if (isNaN(score) || score < 0 || score > 100) {
        console.log("Please enter a valid score between 0 and 100.");
    } else {
        // Check the score using conditionals
        if (score >= 90) {
            console.log("A");  // Grade A for scores 90 and above
        } else if (score >= 80) {
            console.log("B");  // Grade B for scores between 80 and 89
        } else if (score >= 70) {
            console.log("C");  // Grade C for scores between 70 and 79
        } else {
            console.log("F");  // Grade F for scores below 70
        }
    }
}

// Call the function to get a grade
getGrade();

  Cell In[12], line 1
    // Function to get a grade based on score
    ^
SyntaxError: invalid syntax

Hack 3, 3.7.2: PYTHON popcorn

# Function to determine the grade based on a score
def determine_grade(score):
    if score >= 90:
        return "A"
    elif score >= 80:
        return "B"
    elif score >= 70:
        return "C"
    else:
        # Nested conditionals for borderline cases
        if score >= 60:
            print("Borderline case: Checking additional criteria...")
            extra_credit = input("Did the student complete extra credit? (yes/no): ").lower()
            if extra_credit == "yes":
                return "C"
            else:
                return "D"
        else:
            return "F"

# Get user input for the score
try:
    score = int(input("Enter the student's score (0-100): "))
    if 0 <= score <= 100:
        grade = determine_grade(score)
        print(f"The student's grade is: {grade}")
    else:
        print("Please enter a valid score between 0 and 100.")
except ValueError:
    print("Invalid input! Please enter a numeric value.")

Popcorn Hack 4, 3.7.3: js

// Function to assess fitness level based on number of push-ups
function assessFitnessLevel(pushUps) {
    let fitnessLevel;
    
    if (pushUps >= 50) {
        fitnessLevel = "Elite";
    } else {
        if (pushUps >= 30) {
            fitnessLevel = "Advanced";
        } else {
            if (pushUps >= 15) {
                fitnessLevel = "Intermediate";
            } else {
                if (pushUps >= 1) {
                    fitnessLevel = "Beginner";
                } else {
                    fitnessLevel = "Unfit";
                }
            }
        }
    }
    return fitnessLevel;
}

// Example usage
const userPushUps = 28; // You can change this value to test different inputs
console.log(`Fitness Level: ${assessFitnessLevel(userPushUps)}`);